Question

2)f(x) = sin [ x+ (π/2)], 0 ≤ x ≤ (7π/2)

answer choices:
A) maximum value of 1 at x = (9/8)π; min value of -1 at x= (7/8)π
B) maximum value of 1 at x = 0; min value of -1 at x = π
C) maximum value of 1 at x = (7/8)π; min value of -1 at x= (1/8)π
D) maximum value of 1 at x = (1/8)π; min value of -1 at x= (7/8)π
This is the last problem in my homework and I cannot figure it out if anything I don't really understand the question! Can someone show me the steps of how to answer this??? Please and thank you!

Answer 1

Are you certain that you know what the instructions to this question are, and what those instructions are calling for?

You might want to separate that 2) from the rest of your problem statement. At first I was thinking that you actually meant "two times f(x)".