Question

Linear Algebra Question
true or false and why...

Answer 1

any help would be great!

Answer 2

Let \(u\neq v \in R^n\) , since \(T_1\) is not one-to-one, then supposed \(T_1u=T_1v\in R^m \)
\(T_2:R^m\rightarrow R^k\) \(T_2\) sends elements from \(R^m\) to \(R^k\)
\(T_2oT_1~u=T_20T_1~v=(T_2oT_1)~u=(T_2oT_1)~v\)
\(u\neq v\) but \((T_2oT_1)~u=(T_2oT_1)~v\)
that shows \(T_2 ~o T_1\) is not one to one.

Answer 3

that would've been a pain to type, thank you for taking the time!!

Answer 4

:)