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factoring method: 4x^2 - 12x + 9 = 0
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4x^2-12x+9=0 so we can't do this by perfect square, so we'll have to do this normally. 4x^2-12x+9 what are two numbers that equal to ac (=36) when multiplied and those same 2 numbers that equal to b (=12) when added? the numbers are -6 and -6. so now we expand the middle. 4x^2-6x-6x+9 factor by grouping. 2x(2x-3)-3(2x-3) (2x-3)(2x-3) =(2x-3)^2.
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