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Mathematics
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obtain dy/dx 4xy+cos(x/y)=y
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first for the term 4xy \[4(y+x \frac{ dy }{ dx })\]
for the second term cos(x/y) \[-\sin \frac{ x }{ y }*\frac{ y-x \frac{ dy }{ dx } }{ y ^{2} }\]
\[4y+4x \frac{ dy }{ dx }-\frac{ 1 }{ y }*\sin \frac{ x }{ y }+\frac{ x }{ y ^{2} }*\sin \frac{ x }{ y }*\frac{ dy }{ dx }=\frac{ dy }{ dx }\]
collect the coefficients od dy/dx
\[(4x+\frac{ x }{ y ^{2} }*\sin \frac{ x }{ y }-1)=-4y+\frac{ 1 }{ y }*\sin \frac{ x }{ y }\]
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sorry ,the left hand side is multiplied by dy/dx
Oh okay lol
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