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3n^2(u-2)-5(u-2) =[ ] find the complete factored
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\(3n^2(u-2)-5(u-2)\) There is a common factor of \(u-2)\) that you can factor out. Let's look at a similar by different question: if you had: \(3n^2\color{blue}{y}-5\color{blue}{y}\), how would you factor that
If this is what you mean: \( \color{blue}{y}(3n^2-5)\)
Then you can just use the same method of factoring by just replace \(y\) with \(u-2\)
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