Question

Solve the system of linear equations below

x+y=4
2x+3y=0

Answer 1

Rearrange the first equation to get y=4-x. Now we can sub this value of y into the second equation and solve for x:

2x+3(4-x)=0
2x+12-3x=0
-x=-12
x=12

Now we can plug x=12 into either of our original equations to find y. I'll use the first equation:

12+y=4
y=-8

And that's it!

Answer 2

put into y = mx + b form

x+y=4
-x -x

y = -x + 4


2x+3y=0
-2x -2x

3y = -2x + 0
/3 /3

y = -2/3 +0
y = -2/3

Answer 3

Thank you!

Answer 4

Welcome *^.^*