When p equals three, a equals nine, and a varies directly with p, match each value of p with the corresponding value of a. Match Term Definition p equals five A) a equals twelve p equals four B) a equals eighteen p equals two C) a equals six p equals six D) a equals fifteen
\(p=a*k\) for some \(k\in \mathbb{Z}\) \(3=9k\) implies \(k=\frac{1}{3}\) so \(p=\frac{a}{3}a\)
err that shuold say \(p=\frac{1}{3}a\)
p equals five D) p equals four A) p equals two C) p equals six B)
each number is being multiplied by three so that is how you would solve this
@joquez14 can you help me with one more
sure
Thank you Match each set of ordered pairs with their rise over run. Match Term Definition (4, -2), (3, 1) A) -3/7 (4, -2), (-3, 1) B) -1 (-4, -2), (3, 1) C) -3 (-4, 2), (3, 1) D) -1/7
and by help you mean just give the answers
its 3 am im tired! ive been working on this freakin math since 7 am
ok
the rules dont have a section about giving answers to tired people, maybe I missed it....
Bye
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