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Look at this linear equation. 3x + 5y = 30 Which of the following equations can be used to solve for y in the linear equation above?
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y=-3/5x+30 y=3x+6 y=-3/5x+6 y=3/5x+30
@jcpd910
3x + 5y = 30 Isolate y 5y = 30 - 3x Divide it all b 5 to isolate y further y = 6 - 3/5x
which is equivalent to y=-3/5x+6
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