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Mathematics 15 Online
OpenStudy (anonymous):

ab-2ac+b^2-2bc

OpenStudy (anonymous):

@JungHyunRan

OpenStudy (anonymous):

\(ab-2ac+b^2-2bc=(ab+b^2)-(2ac+2bc)\\=b(a+b)-2c(a+b)=(a+b)(b-2c)\)

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