Question

@Dscdago In circle A shown below, mArc BC is 67° and mArc EF is 74°:

Points B, C, E, F lie on Circle A. Lines BE and CF pass through point D creating angle EDF. Measure of arc BC is 67 degrees and measure of arc EF is 74 degrees.

What is m∠FDE?

37°

74°

70.5°

33.5°

Answer 1

Okay. So the formula for this problem is \[\angle FDE= \frac{ 1 }{ 2 }( arc BC+ arc FE)\]
This says to add arc BC and arc FE. Then you find halve of it.

Answer 2

so i do 67 + 74 ?

Answer 3

Yes. Then find halve of it and you have your answer :)

Answer 4

C