Question

(dz/dt) + 3e^(t+z) = 0
Medal for showing me this! :)

I got z = -3e^t but it's wrong, can someone help please? This is for calc 2

Answer 1

my assignment also asks to use C for any constant

Answer 2

dz/dt=-3e^t*e^z
e^-zdz=-3e^tdt
integrating at both sides
-e^-z=-3e^t+c
e^-z=3e^t-c
e^z=1/(3e^t-c)

Answer 3

thank you I see what I did wrong now

Answer 4

welcome!