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A cat with a mass of 4.50 kilograms sits on a ledge 0.800 meters above the ground. If it jumps to the ground, how much kinetic energy will it have just as it reaches the ground? 35.3 J 3.60 J 0.350 J cannot be determined
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KE= 0.5 x mass x velocity^2 GPE = m x g x h GPE = KE 4.5 x 0.8 x 9.81 = 35.316 J Answer is 0.350 J 0.00100 x 0.5 x 2.2^2 = 2.42 x 10^-3 J
thank you so much
No problem! (:
the first answer you wrote was correct, 4.5 x 0.8 x 9.81 = 35.316 J it seems like you copied and pasted from somewhere lol
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