So I got a question wrong on my test and trying to figure out how to solve it. Help?
A rectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. Find the area of the rectangle. 2 to the 3 over 5 power inches squared 2 to the 4 over 5 power inches squared 2 inches squared 2 to the 2 over 5 power inches squared
I put the first one.
The correct answer is 2 in. squared.
Ok, but how did you find that out?
Write down what you know. \[L = \sqrt[5]{16}\]\[W = 2^{\frac{ 1 }{ 5 }}\] Figure out what you are asked to solve. Area of a Rectangle \[A_{rectangle} = Length \times width\] Plug and Chug.
ok... so you have to rewrite 16 as a power of 2 so its |dw:1403732306554:dw| use the previous rule.. then you can multiply the same base and add the powers..
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