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For the function y = f(x), what is the ordered pair for the point on the graph when x = b - 2? (b - 2, f(b -2)) (x, f(b)) (x, b - 2) (b - 2, f(b))
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Well, it SAYS x = b-2, so the second and third must be discarded. Now what?
All we have left is... (b - 2, f(b -2)) and (b - 2, f(b))
That function notation means you substitute the particular value given. Which function argument actually contains the ENTIRE x-value?
I deleted your entirely false statement about how bad you are. Don't say it or think it again!
A?
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CAuse D doesn't have the -2 at the end of the b?
There you go! So much for being horrible. Move on to the next one.
Okay, can you help me with this one? It's slopes.
Post a new thread.
Alright.
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