find the product of
2n^2+4n+4)(4n-5)

a. 8n^3+26n^2-36n-20
b. 8n^3+6n^2-4n-20
c. 8n^3+4n^2-6n-20
d. 8n^3-6n^2+36n-20

Question

find the product of
2n^2+4n+4)(4n-5)

a. 8n^3+26n^2-36n-20
b. 8n^3+6n^2-4n-20
c. 8n^3+4n^2-6n-20
d. 8n^3-6n^2+36n-20

anonymous · Answer

please someone give me the answer

kropot72 · Answer

We can help you to find the answer if you like.

anonymous · Answer

yes please

kropot72 · Answer

$$Product=2n ^{2}(4n-5)+4n(4n-5)+4(4n-5)\ .............(1)$$
Now you need to remove the brackets and collect the like terms.

kropot72 · Answer

@athorn2422 Do you know how to remove the brackets?

anonymous · Answer

@kropot72  your making it very complicated by doing it like that

anonymous · Answer

just multiply

kropot72 · Answer

Multiply each term inside the brackets by the term outside the brackets. For example:
$$5x ^{3}(7x-20)=35x ^{4}-100x ^{3}$$

kropot72 · Answer

@FriedRice Yes, we are just multiplying!

anonymous · Answer

okay

anonymous · Answer

no a easy way by cross multiplying like this
2n^2+4n+4)(4n-5)
8n^3 + 16n^2 + 16n -10n^2 - 20n -20
8n^3 + 6n^2 + 4n - 20

instead of doing
Product=2n2(4n−5) + 4n(4n−5) + 4(4n−5)

kropot72 · Answer

@FriedRice Would you please refrain from working through to a complete answer.

anonymous · Answer

well you are cross multiplying like this
|dw:1403764889678:dw|