A car is driven along a level road . Total energy input from the petrol is 60kj & the car wastes 45kj of energy . What is the eficiency of the car?
What do u think ?
75%
(45/60)*100
Efficiency = \(\huge\frac{Output}{input}\)
Here, car wastes 45KJ thus it gives an output of only 60-45=15KJ
got it ?
yes
*wasted
so efficiency will be (15/60)*100=25%
thanks dear friend
\(\huge\color{red}\bigstar\)\(\huge\text{Rectification}\) \(\huge\color{red}\bigstar\) \(\color{blue}{\text{Originally Posted by}}\) @Abhisar Efficiency = \(\huge\frac{Output}{input}\) *100 \(\color{blue}{\text{End of Quote}}\)
\(\color{red}{\huge\bigstar}\huge\text{You're Most Welcome! }\color{red}\bigstar\) \(~~~~~~~~~~~~~~~~~~~~~~~~~~~\color{green}{\huge\ddot\smile}\color{blue}{\huge\ddot\smile}\color{pink}{\huge\ddot\smile}\color{red}{\huge\ddot\smile}\color{yellow}{\huge\ddot\smile}\)
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