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Prove the identity sinx/1+cosx=1-cosx/sinx
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Multiply by the conjugate
\[Sinx \div1+cosx, Sinx/1+sinx/cosx, sinx*cosx+sinx/cosx\]
you haven't multiplied the numerator and denominator by the conjugate 1-cosx
\[\frac{ \sin x }{ 1+\cos x } \times \frac{ 1-\cos x }{ 1-\cos x }\] \[= \frac{ \sin x(1-\cos x) }{(1^{2}-\cos ^{2}x) }\] \[=\frac{ \sin x(1-\cos x) }{ \sin ^{2}x }=\frac{ (1-\cos x) }{ \sin x }\]
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