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Biology 15 Online
OpenStudy (anonymous):

Consider the following cross: Parent 1: YyTt Parent 2: YyTt Using the rules of probability, determine the probability that the offspring will show YyTT genotype? 1/8 1/16 1/2

OpenStudy (anonymous):

@flvsguy

OpenStudy (anonymous):

c

OpenStudy (anonymous):

i hate these questions though

OpenStudy (abhisar):

How c ?

OpenStudy (anonymous):

i did a cross but i hate these questions and i told him on the last one too check these with other poeple

OpenStudy (abhisar):

I'll tell u guys a easy trick to do this without cross

OpenStudy (anonymous):

IM NOT A HIM !

OpenStudy (anonymous):

Her xD

OpenStudy (anonymous):

BUTTHEAD !

OpenStudy (abhisar):

That's RUDE @HisOnlyForever !

OpenStudy (anonymous):

How ?

OpenStudy (abhisar):

ohkay lets see the trick

OpenStudy (abhisar):

Since parent 1 has Yy, probability of getting one y from him/her will be 50 %

OpenStudy (abhisar):

agree ?

OpenStudy (abhisar):

??

OpenStudy (abhisar):

Now probability of getting Y from parent 2 is also 50%

OpenStudy (abhisar):

Combined probability of getting Y & y together will be 25%

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