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PLS HELP!!!!!!!!!!! Solve the radical inequality. square root (x + 2) less than equal to x- 10
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Try to square both sides. Also, ignore solutions (if any) that do not satisfy the original equation.
|dw:1403793568000:dw|
how do i solve frm there
You should write the inequality like this first.\[0 \le \sqrt{x-2} \le x - 10\]
ok..
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then do i square both sides?
Yes, you do.
can u pls share what you get when you square both sides
\[(\sqrt{x+2})^2 \le (x -10)^2\]\[x + 2 \le x^2 - 20x + 100\]
|dw:1403794118220:dw|
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