Question

Solve for x. State any restrictions on the variables.
a(x-3)+8=b(x-1)

Answer 1

a(x-3)+8=b(x-1)
a(x-3)+8-b(x-1)=0
ax-3a+8-bx+b=0
x(a-b)-3a+b+8=0
\[\Huge x=\frac{3a-b-8}{a-b}\]
Restrictions on variable :
\[\Huge a \neq b\]
otherwise function becomes indeterminate.