Question

A textbook search community is considering 17 books for possible adoption. The committee decided to send only 8 out of the 17...in how many ways can it do so

Answer 1

C(17,8)

Answer 2

17/8
17 -8
9
after these steps what do I do?

Answer 3

\[\Huge C(17,8) = \frac{17!}{9! 8!}\]

Answer 4

count down to 8 from 17?

Answer 5

These are different groups of books, each group being in no particular order. So you want the number of combinations of the 17 books taken 8 at a time.
\[17C8=\frac{17!}{8!9!}=\frac{17\times16\times15\times14\times13\times12\times11\times10}{8\times7\times6\times5\times4\times3\times2}\]

Answer 6

17! = 17x16x15x14x13x12x11x10x9!