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OpenStudy (anonymous):
@hartnn
hartnn (hartnn):
lets take left side first.
4 csc 2x
convert csc x to sin x, know how ?
OpenStudy (anonymous):
csc = 1/sin
OpenStudy (anonymous):
how would I write that? The 4 and 2x are confusing me
hartnn (hartnn):
now csc 2x = 1/ sin 2x
4 csc 2x
= 4/ sin 2x
you know the formula for sin 2x ?
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OpenStudy (anonymous):
No
hartnn (hartnn):
sin 2x = 2 sin x cos x
plug this in
OpenStudy (anonymous):
4/2 sin x cos x
hartnn (hartnn):
ys, and 4/2 = 2
so for left side we have
2/(sin x cos x)
now we will try to simplify the right side, and check whether we get same expression.
2 csc^2 x tanx
convert both csc x and tan x in terms of sin x and cos x
can u
OpenStudy (anonymous):
we would change csc^2 to cot^2 + 1?
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hartnn (hartnn):
since we know csc x = 1/sin x
try replacing
csc^2 x by 1/ sin^2 x
OpenStudy (anonymous):
2/sin^2x
hartnn (hartnn):
and what about that tan x ?
OpenStudy (anonymous):
sin x/cos x
hartnn (hartnn):
yes, so
|dw:1404011250147:dw|
what does that simplify to ?