Please Help,
Jon rented a car from a company that charged a daily rental fee and a mileage charge. He rented the car for 7 days and drove 400 miles and was charged $345. His friend Amanda later rented the same car for 8 days and drove 380 miles and was charged $375. What was the daily rental charge? How much did the company charge per mile?

I dont even know where to begin please help.

Question

Please Help,
Jon rented a car from a company that charged a daily rental fee and a mileage charge. He rented the car for 7 days and drove 400 miles and was charged $345. His friend Amanda later rented the same car for 8 days and drove 380 miles and was charged $375. What was the daily rental charge? How much did the company charge per mile?

I dont even know where to begin please help.

precal · Answer

This looks like a system of equations.  What type of class are you taking?

precal · Answer

I ask because you went from a quadratic to a system.

precal · Answer

you need to use x and y 
Let's call x = rental days
y= mileage

precal · Answer

He rented the car for 7 days and drove 400 miles and was charged $345.

precal · Answer

7x+ 400y=345
7 days is 7x 
and is your +
400 miles is your 400y
charged 345 is =345

anonymous · Answer

Just college algebra 110

precal · Answer

Can you write the second equation we will need?

precal · Answer

Is this an online course?

precal · Answer

His friend Amanda later rented the same car for 8 days and drove 380 miles and was charged $375

anonymous · Answer

Yes and I am working on my final right now and honestly I do not remember any of this

precal · Answer

You will need this statement to create the second one.

precal · Answer

I gotta go soon so can you write your second equation.

anonymous · Answer

8x+380y=375

precal · Answer

yes

precal · Answer

8x+380y=375
7x+ 400y=345

precal · Answer

If you are given multiple choices, you can sub your x and y values to find the true statements.  For example is they said (1,2) or 1 day and $2 a mile
8(1)+380(2) is 768 so that would not be the solution.

precal · Answer

You can bypass solving this using algebraic methods if you are given multiple choices.  Just substitute your given choices and they do have to work for both equations.  Good luck on your final. Gotta go :)

anonymous · Answer

Thank you I appreciate your time.

precal · Answer

anytime

imstuck · Answer

Those equations that precal gave you..do you know how to solve them simultaneously?

precal · Answer

He/She does not know how to solve them.  In that case, the best way to solve it (if given values) is to substitute them.  @IMStuck