Basic trigonometry, I have a solution, want someone to check, I'll type in comment section :)
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The calculator is showing me, 2 - square root of 3 . How do I get there?
multily numerator n denominator by √3-1
ohh we need to rationalize, can someone help me with that? :)
so so far you get, -1+√3 ------ 1+√3 re-phrasing, √3 - 1 ----- √3 + 1 then multiply both top and bottom times √3 - 1
hmm wait up Ill try it on paper
Sure, go ahead...
(square root of 3 -1)^2 is FOIL method right? same as polynomials?
yes. (a-b)² = (a-b)(a-b) = a²-2ab+b² Also, To get √ , Click and hold ALT, click 2 5 1 on the number pad on the right, release ALT. To get ² , Click and hold ALT, click 2 5 3 on the number pad on the right, release ALT. To get ³ , Click and hold ALT, click 0 1 7 9 on the number pad on the right, release ALT.
pardon, the typings I use only laptop :) and thank you :)
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