the sum of three consecutive even integers is 108. Find the integers?
got a number? gimme any number
x+(x+2)+(x+4)=108 3x+6=108 3x=102 x=34 SO your 'three' numbers would be 34, 36, 38.
My apologies, the number was 195.
But thank you, man.
the sum of three consecutive integers is 108. Find the integers?
I had the correct answer, but whenever I put it in.. it keeps saying incorrect.
ahemm "the sum of three \(\underline{consecutive}\) even integers"
Oh
Idk why I did that then
well.. actually 34, 36 and 38 are indeed ...
No that was right.
not even, just the sum of three consecutive integers
Now im hella confussed what numbers were even talking about now.
for 195, not 108. The sum of three consecutive integers is 195. Find the integers.
what the ?
EVEN OR NOT!
You are all over the place.
The sum of three consecutive integers is 195. Find the integers.
heheh
-_-
My apologies...
a+a+1+a+2+a+3+a+4=195, 5a+10=195, 5a=185,a=37,they are; 37,38,39,
I gave up on this problem about 20 minutes ago sorry
x = 1st number x + 1 = 2nd number x + 2 = 3rd number x + x + 1 + x + 2 = 195 3x + 3 = 195 3x = 195 - 3 3x = 192 x = 192/3 x = 64 x + 1 = 65 x + 2 = 66 your numbers are : 64,65,66
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