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sqrt 7x (sqrt x -7 sqrt 7) ?
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\[\sqrt{7x}(\sqrt{x}-7\sqrt{7})\]
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\[\sqrt{a} * \sqrt{b} = \sqrt{a*b}\]
So first use distributive property that is if we have x * (a - b) = x * a - x * b Then use above rule ,,
So using distributive property we get \[\sqrt{7x}*(\sqrt{x } - 7\sqrt{7}) = \sqrt{7x}*\sqrt{x} - \sqrt{7x}*7\sqrt{7} \]
Now use √a∗√b=√(a*b) So we get \[\sqrt{7x^2} - 7*\sqrt{x*7^2} = x \sqrt{7} - 7*7\sqrt{x}= x \sqrt{7} - 49\sqrt{x}\]
thanks :)
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You are welcome :) Sam :)
sorry i just saw this :(
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