Question

Find all solutions by factoring:
t^2+9t+18=0

Answer 1

What two numbers when added to together equal 9 and when multiplies together equal 18?

Answer 2

3 and 6

Answer 3

So to get t^2 what do you have to do?

Answer 4

(t+3)(t+6)=0

Answer 5

Very good..now what are the values for t going to be?

Answer 6

???

Answer 7

(t+3)(t+6)=0. When you factor an equation that equals 0 you then take each factor and solve for 0 to get your possible solutions..ie t+3=0..What would the value for (t) be?

Answer 8

0

Answer 9

so are the solutions: (0,3,6)

Answer 10

No. You have factored the equation correctly when you came up with (t+3)(t+6) =0.

So the value for t in the equation t+3=0 we solve by subtracting 3 from both sides and we get t+3-3=0-3 or t=-3. So one solution for t is (-3). Now what would be the other solution?

Answer 11

0

Answer 12

No. Look at it this way in the equation (t+3)(t+6)=0 We are multiplying correct. So if we multiply anything by 0 we get 0. So by making t = -3 the equation becomes

(-3+3) (-3+6) = 0 or 0 times 3 which equals 0. Do you see this?

Answer 13

yes

Answer 14

In factoring when the results equal zero all we need to do is take each factor and solve it for 0.
So t+3 = 0 then t has to be -3
So t+6 =0 then t has to be ?

Answer 15

-6

Answer 16

Good job

Answer 17

so the solution set is (-3, -6)

Answer 18

You got it

Answer 19

thank you