If line FE = 14 would Line BC = 28?

Figure in comments. (anyone know how to add it in post?

Question

If line FE = 14 would Line BC = 28?

Figure in comments. (anyone know how to add it in post?

anonymous · Answer

Is there like a formatting guide for this site? I'm still a newbie. >.<

anonymous · Answer

@jim_thompson5910  Know how to do this one?

jim_thompson5910 · Answer

Notice the tick marks on the left side of the triangle

They imply that 

AF = FG = GB

jim_thompson5910 · Answer

So

AB = AF + FG + GB

AB = AF + AF + AF

AB = 3*AF

jim_thompson5910 · Answer

The triangles are similar, which means their sides form this proportion

AF/AB = FE/BC

anonymous · Answer

Hmm. I don't get how that helps me solve it though :/

jim_thompson5910 · Answer

Now you plug in AB = 3*AF into the equation to get


AF/AB = FE/BC

AF/(3*AF) = FE/BC

anonymous · Answer

Ohhhhh. would it be 42 then?

jim_thompson5910 · Answer

The AF terms will divide and cancel 

1/3 = FE/BC

and then you cross multiply to get


1*BC = 3*FE

BC = 3*FE

jim_thompson5910 · Answer

yep BC = 42

anonymous · Answer

YES! You're really helpful. Thanks so much <3 :)

jim_thompson5910 · Answer

you're welcome

anonymous · Answer

@jim_thompson5910  What about this one?  :P

anonymous · Answer

If UV = 29 & WZ = 40, What does XY equal?

anonymous · Answer

Also if Line XW is equal to Line YZ and m∠Z = 72 degrees what is m∠x?

jim_thompson5910 · Answer

If UV = 29 & WZ = 40, What does XY equal?

jim_thompson5910 · Answer

use the midsegment theorem

(XY + WZ)/2 = UV

(XY + 40)/2 = 29

solve for XY

anonymous · Answer

No idea what that is.. How do you remember all this stuff?! o.O

jim_thompson5910 · Answer

do you know how to solve (XY + 40)/2 = 29 ?

anonymous · Answer

Noooo! I'm lost >.<

jim_thompson5910 · Answer

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