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OpenStudy (anonymous):
Solve 2cos2Θ/2 = cos2Θ for 0º≤Θ≤360º.
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OpenStudy (anonymous):
So, basically solve cos(2Theta) = cos(2Theta)?
OpenStudy (anonymous):
I'm asking because I'm not sure what you need to do here. It boils down to cos(2Theta) = cos(2Theta).
OpenStudy (goformit100):
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