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Trying to solve: x^2-11x+30=0
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what pair of factors of 30 add to -11?
5 &6
Remember your signs.
(x+5)(x-6)
notice 5 times -6 = -30 5 plus -6 = -1
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they need to go the other way around?
(x+6)(x-5)
Remember your signs.
What two values add up to 'negative' eleven. - 11
-6 + -5
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Correct they are both negative now re-write your previous factoring
(x-6)(x-5)
Correct
Now you can set the 2 different terms equal to 0 separately and solve for x.
Another method you could use to solve a Quadratic Equation in the form \[ax^2+bx+c = 0\] Is the Quadratic Formula: \[x =\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
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you dont have to go that far. lol you can say that x = 6 and 5
thank you both
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