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Mathematics 14 Online
OpenStudy (kanwal32):

For the A.P given by a1,a2,....,an,....,with non zero common difference, the equation satisfied are A)a1+2a2+a3=0 D) a1-4a2+6a3-4a4+a5 B)a1-a2+a3=0 (one than more correct options) C)a1+3a2- 3a3 -a4=0

OpenStudy (kanwal32):

@dan815 @goformit100 @ParthKohli pls help

OpenStudy (kanwal32):

@hartnn pls help

OpenStudy (kanwal32):

@goformit100

OpenStudy (anonymous):

oh my nyan cat!!!! Impossible!!! srry!

OpenStudy (kanwal32):

@goformit100 @dan815 pls help

OpenStudy (kanwal32):

@ganeshie8 pls help

OpenStudy (kanwal32):

pls help i have a exam of sequence and series on 6th

Parth (parthkohli):

one way is to actually consider an AP.

OpenStudy (kanwal32):

yes

OpenStudy (kanwal32):

sir

Parth (parthkohli):

i'm thinking of using arithmetic means... one sec.

OpenStudy (kanwal32):

(a1 here 1 is in subscript)

OpenStudy (kanwal32):

i think yes we will use AM here an as theam

Parth (parthkohli):

you can also construct terms. for three terms, use \(a-d,a, a+d\) and so on. if all the terms don't get cancelled, then it doesn't evaluate to zero.

OpenStudy (kanwal32):

i tried the same but couldn't get the answer

Parth (parthkohli):

the only option being satisfied for the AP 1, 2, 3, 4, 5 is D.

OpenStudy (kanwal32):

pls tell

OpenStudy (kanwal32):

no one @ganeshie8 pls help

OpenStudy (kanwal32):

@goformit100 pls help

ganeshie8 (ganeshie8):

consider a simple A.P like @ParthKohli suggested ?

OpenStudy (kanwal32):

ok

ganeshie8 (ganeshie8):

like below : 0, 1, 2, 3, 4, 5,...

ganeshie8 (ganeshie8):

\(a_1 = 0\) \(a_2 = 1\) \(a_3 = 2\) \(a_4 = 3\) \(a_5 = 4\)

ganeshie8 (ganeshie8):

simply plugin the values in each option and check which one satisfies

ganeshie8 (ganeshie8):

lets try first option : `A)a1+2a2+a3=0`

ganeshie8 (ganeshie8):

plugin a1, a2, a3 values and see what you get

OpenStudy (kanwal32):

I shold take these problem like this u have suggested

OpenStudy (kanwal32):

thnx

ganeshie8 (ganeshie8):

np :)

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