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Need help pleasee!!!! Find the radius and center of the circle given by the equation below. (x-6)^2+(y+4)^2=7 A.r=7 and center at (-6,4) B.r=7 and center at (6,-4) C.r=sqrt7 and center at (-4,6) D.r=sqrt7 and (6,-4)
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nevermind people
The answer is B.
thanks man
actually it is not B
It is not B. the 7 is also squared, therefore the actual radius is √7 or D.
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ohhh thanks good thing i have a retry
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