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solve this (5-z)(3z+8)=0
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What you do here is set each parenthesis equal to 0 and solve for z. The first one, then, would be 5 - z = 0...-z = -5...or z = 5. The next one would be 3z + 8 = 0...3z = -8...z = -8/3
i got -8/3
Very good! Those are your solutions to the original quadratic equation (which they didn't give you in its standard form; they already factored it for you).
\[-3 z^2+7 z+40 = 0\] this is a quadratic equation which gives to solutions -8/3 and 5.
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