Question

How many roots does the polynomial function, y=(x-8)(x+3)^2 have?
A. 2
B. 3
C. 4
D. 1

Answer 1

\(\large { y=(x-8)(x+3)^2\implies y=(x-8)(x+3)(x+3)
\\ \quad \\
\qquad
\begin{cases}
0=(x-8)\implies 8=x\\
0=(x+3)\implies -3=x\\
0=(x+3)\implies -3=x
\end{cases}\implies x=\{8,-3\} }\)

Answer 2

it has 3 roots, but one of them has a "multiplicity" of 2
that is is there twice

so it really has only 2 roots

Answer 3

Thank you!

Answer 4

yw