Question

Find the exact value of tan[cos^-1(1/3)]

Answer 1

\(\bf cos^{-1}\left(\frac{1}{3}\right)=\theta\implies cos(\theta)=\cfrac{1}{3}\to \cfrac{adjacent}{hypotenuse}\to \cfrac{a=1}{c=3}\)

\(\bf recall\implies tan(\theta)=\cfrac{opposite}{hypotenuse}\to \cfrac{b}{c}\)