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Mathematics 27 Online
OpenStudy (anonymous):

find any critical numbers for f(x)=x^2/x-1

OpenStudy (anonymous):

\[f(x)=\frac{x^2}{x-1}\] right?

OpenStudy (anonymous):

yes i didnt use the equation button for some reason

OpenStudy (anonymous):

i can see it on my calculator but i need to show my work

OpenStudy (anonymous):

did you get \[f'(x)=\frac{x^2-2x}{(x-1)^2}\]?

OpenStudy (anonymous):

oh using quotient that makes sense

OpenStudy (anonymous):

no choice really now they are easy to find set the numerator equal to zero, solve for \(x\)

OpenStudy (anonymous):

ok thank you

OpenStudy (anonymous):

yw

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