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Mathematics 7 Online
OpenStudy (phebe):

|x+3_<5 @jim_thompson5910

jimthompson5910 (jim_thompson5910):

|x+3| < 5 ??

OpenStudy (phebe):

yea thas the prob

jimthompson5910 (jim_thompson5910):

in general, if we have |x| < k for some positive number k, then -k < x < k

OpenStudy (phebe):

ok

jimthompson5910 (jim_thompson5910):

So in this case, we have |x+3| < 5 that breaks up into -5 < x+3 < 5

jimthompson5910 (jim_thompson5910):

now solve -5 < x+3 < 5 for x

OpenStudy (phebe):

is the answer -8<x<2

jimthompson5910 (jim_thompson5910):

very good

jimthompson5910 (jim_thompson5910):

you subtract 3 from all sides to get that

OpenStudy (phebe):

yess thanx another one plzz so i can make sure im on the right page now

OpenStudy (phebe):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

go ahead

OpenStudy (phebe):

ok ima post it k

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