The coefficients corresponding to k = 0, 1, 2, ..., 5 in the expansion of (x + y)^5 are _____.
A. 1, 5, 10, 10, 5, 1
B. 1, 5, 10, 5, 1
C. 0, 1, 5, 10, 5, 1, 0
D. 0, 5, 10, 10, 5, 0

Question

The coefficients corresponding to k = 0, 1, 2, ..., 5 in the expansion of (x + y)^5 are _____.
  		A. 	1, 5, 10, 10, 5, 1
  		B. 	1, 5, 10, 5, 1
  		C. 	0, 1, 5, 10, 5, 1, 0
  		D. 	0, 5, 10, 10, 5, 0

anonymous · Answer

this is binomial theorem do you know about it

zab505 · Answer

kind of

zab505 · Answer

I attempted it in that form but could not get it?

anonymous · Answer

its A.. try to multiply the term 5 times..

zab505 · Answer

k

zab505 · Answer

but so then A?

zab505 · Answer

Ah I got it you were right! Thank you so much!

anonymous · Answer

ur welcome...

dumbcow · Answer

the coefficients come from combinations 5 choose 0 5 choose 1 ... 5 choose 5 http://en.wikipedia.org/wiki/Combination