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The coefficients corresponding to k = 0, 1, 2, ..., 5 in the expansion of (x + y)^5 are _____. A. 1, 5, 10, 10, 5, 1 B. 1, 5, 10, 5, 1 C. 0, 1, 5, 10, 5, 1, 0 D. 0, 5, 10, 10, 5, 0
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this is binomial theorem do you know about it
kind of
I attempted it in that form but could not get it?
its A.. try to multiply the term 5 times..
k
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but so then A?
Ah I got it you were right! Thank you so much!
ur welcome...
the coefficients come from combinations 5 choose 0 5 choose 1 ... 5 choose 5 http://en.wikipedia.org/wiki/Combination
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