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What is the quotient when (x + 3) is divided into the polynomial 2x2 + 3x - 9? A. x + 3 with a remainder of -2 B. 2x - 3 with no remainder C. 2x + 1 with no remainder D. 2x - 5 with no remainder
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when you factor 2x^2+3x-9 what do you get?
you know one of the factors could be (x+3)
Would it be b?
you could expand out (x+3)(2x-3) to find out, try expanding it and I will double check your expansion
how?
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distribute x to (2x-3) then distribute 3(2x-3) and then combine like terms
if it is the correct solution it will match 2x2 + 3x - 9
2x^2+6x-9
(x+3)(2x-3) 2x^2-9x+6x-9 2x^2-3x-9
does it match?
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yeah
So then it would be B?
?
are you there?
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