Question

₆P₃

Answer 1

???????

Answer 2

6!/3!=6*5*4*3*2*1/6=5*4*3*2=120

Answer 3

\(\Large _nP_r = \dfrac{n!}{(n-r)!}\)

Answer 4

plug in values and you will get what @cody_123 have

Answer 5

yes

Answer 6

I got 20