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Solve (x + 1 < 5) ∩ (x - 4 > -3). a. {all real numbers} b. {x | 1 < x < 4} c. {x | x < 4 or x > 1}
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x < 4 AND x > 1 Just solve with simple algebra
Pretty sure.
c would be the answer if you had a \(\cup\)
@zzr0ck3r - So C is not the correct answer?
no
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@xGuardians is correct
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