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Find the dimensions of a rectangle with area 343 m2 whose perimeter is as small as possible. (If both values are the same number, enter it into both blanks.)
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Is there like a diagram of sorts?
No. The question was the only thing given.
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I can't find anything..
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perimeter = 2x+2y Area = xy = 343 --> y = 343/x --> p(x) = 2x + 2(343/x) to minimize, set derivative equal to 0 --> 2 - 686/x^2 = 0 --> x^2 = 343 x = sqrt(343)
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