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the distance between the teams in first and second place is 5.7 meters. the distance between the teams in second and third place is one-thrd that distance.how much farther ahead is the team in first place than the team in third
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5.7 * 1/3 = x x + 5.7 = the distance between team 1 and 3
my options are 1.9,5.7,7.6, and 2.5
did you solved what I just gave you?
solve 5.7 * 1/3 first. You will get x. Then whatever you get from 5.7* 1/3 add it 5.7 again which is the distance of team 1 and 2. We are simply adding up the distance of each team to the point where we obtain the distant total between team 1 and 3.
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