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(2/x - 2) + (7/x^2 - 4) = (5/x)
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Okay, the LCD is x(x - 2)(x + 2). I'll multiply everything by that to get rid of the denominators.
@phi brb
I would multiply both sides (and all terms) by x(x-2)(x+2)
Yes, that's what I said :)
oh, I missed your first post.
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It's okay. I'm working that out now. Hold on a second.
Since the denominators all cancel out, I believe I get 2x^2 + 4x + 7x = 5x^2 - 20...I'll write it with the denominators
now collect like terms
|dw:1404252815532:dw|
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