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Find the domain of the function \[g(x)=\frac{ 3x }{ x^2-81 }\] fractions throw me all over the world every time that I see them I swear
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You cant have a zero denominator so try making \[x^{2}+81 \neq 0\]
domain will be everything but that
erh... got a typo
correction, \[x^{2}-81 \neq 0\]
\[(\infty,-9)\] ?
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noo.... \[x^{2}-81 \neq 0 <=> x^{2}=81 => x=9 or x=-9\] Domain ]-inf, -9[ U ]9,+inf[
DANG IT! >-< thank youuu lol
erh...it was wrong, sorry, its R except -9 and 9
R\{-9,9}
I see, it's okay c: thank you
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