Ask your own question, for FREE!
Mathematics 29 Online
OpenStudy (anonymous):

Solve for x. -ax + 3b > 5 x > the quantity 3 times b minus 5 all over negative a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over negative a x < the quantity negative 3 times b plus 5 all over negative a

OpenStudy (anonymous):

it's really not that hard... come on, at least try, start by getting only -ax> something

OpenStudy (anonymous):

subtract 3b from both sides right

OpenStudy (anonymous):

so -ax > 5 - 3b

OpenStudy (anonymous):

@Syderitic

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!