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Mathematics 8 Online
OpenStudy (anonymous):

anyone help me :)

ganeshie8 (ganeshie8):

use a proportion : \[\large \dfrac{1.5}{12} = \dfrac{x}{16} \]

OpenStudy (anonymous):

the answer is 2 ohm

ganeshie8 (ganeshie8):

Yep !

OpenStudy (anonymous):

thanks

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