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A 5.00kg block slides down a frictionless plane inclined 30∘ to the horizontal. By what force is the work done?
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Gravity, I believe. If the question is really about how much force is used we can assume that gravity is the only force acting on the block as they specify no other. This means the force F = 5 * 9.81 F = 49.05 kg m s^-2
That makes sense. Thank you!
Your welcome :)
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