Question

A 6.0kg box slides a 20m distance on ice. If the coefficient of kinetic friction is 0.25, what is the work done by the friction force?

Answer 1

work done = force . displacement
= (coeff of friction * normal) * 20
= .25 * 6 * 9.8 * 20
=294 J

Answer 2

provided the sliding is on a plane suface with elevation angle 0

Answer 3

actually its -294 J

Answer 4

@sstaton
Is your query cleared? :)

Answer 5

Yes thank you!