Question

Evaluate for x = 2 and y = 3: x^2-y^-3/x^-1y

Answer 1

Input 2 for x and 3 for y.

Answer 2

\(\Large\frac{x^2-y^{-3}}{x^{-1}y}\)

\(\Large\frac{(2)^2-(3)^{-3}}{(2)^{-1}(3)}\)

Can you simplify @sarah841

Answer 3

.3 is a rational number?

Answer 4

i got 34/9 idk

Answer 5

\(\Large\frac{4-0.04}{(0.5)(3)}\)

Answer 6

\(\Large\frac{3.96}{1.50}\)

Can you divide that? @sarah841

Answer 7

2.64

Answer 8

Correct.

That's your answer..

Answer 9

yay

Answer 10

im confused though because the answer is supposed to be 8/81 or 2/9 or 1/648

Answer 11

Do you have choices?

Answer 12

yes

Answer 13

8/81 or 2/9 or 1/648

Answer 14

Oh

Answer 15

yes

Answer 16

Well..it can be the fraction 214/81..but idk..